Question

A population has a mean $\mu = 139$ and a standard deviation $\sigma = 28$. Find the mean and standard deviation of the sampling distribution of sample means with sample size $n = 51$. The mean is $\mu_{\bar{x}} = \boxed{\text{ }}$, and the standard deviation is $\sigma_{\bar{x}} = \boxed{\text{ }}$. (Round to three decimal places as needed.)

          A population has a mean $\mu = 139$ and a standard deviation $\sigma = 28$. Find the mean and standard deviation of the sampling distribution of sample means with sample size $n = 51$.
The mean is $\mu_{\bar{x}} = \boxed{\text{ }}$, and the standard deviation is $\sigma_{\bar{x}} = \boxed{\text{ }}$.
(Round to three decimal places as needed.)

A population has a mean μ = 139 and a standard deviation σ = 28. Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 51.
The mean is μx̅ =, and the standard deviation is σx̅ =.
(Round to three decimal places as needed.)

Added by Gina O.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Jeremy Gamble

08/01/2023

Step 1

Step 1: Calculate the mean of the sampling distribution of sample means (\mu_{\bar{x}}): The mean of the sampling distribution of sample means is equal to the population mean, so: \mu_{\bar{x}} = \mu = 139 Show more…

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A population has a mean mu =139 and a standard deviation sigma =28. Find the mean and standard deviation of the sampling distribution of sample means with sample size n=51. The mean is mu _(ar{x} )=, and the standard deviation is sigma _(ar{x} )= (Round to three decimal places as needed.) A population has a mean = 139 and a standard deviation =28.Find the mean and standard deviation of the sampling distribution of sample means with sample size n=51 The mean is =[. and the standard deviation is =. (Round to three decimal places as needed.)