00:01
If i were trying to do a population with doubling time, i would take the initial population and use my base to be 2 to the t over k power, where k is represented of the doubling time.
00:15
So if you want to figure out the doubling time, you can take the initial population of 100.
00:22
I'm going to leave this 2 alone, and k is, we don't know yet, but we do know that after 18 hours, we're up to 170.
00:33
So at this point i can figure out, because i can divide the hundred over, that reduces, that cancels, then i can natural log both sides.
00:46
The reason i like to match a log both sides is then i can move that 18 over k in front of the natural log of 2.
00:52
You can do any log you want.
00:54
This is actually 1 .17.
00:57
So to solve for k, i'd have to multiply it over here.
01:03
So to solve for k then, it's that 18 natural log of 2.
01:07
Divided by the natural log of 1 .17.
01:11
And now i'm going to a calculator, just typing that in.
01:16
18 ln2 over ln1 .17...