A population of values has a normal distribution with μ = 103.4 and σ = 15.2 You intend to draw a random sample of size n = 237 . Find the probability that a single randomly selected value is greater than 104.8. P(X > 104.8) = Find the probability that a sample of size n = 237 is randomly selected with a mean greater than 104.8. P(M > 104.8) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Added by Jose H.
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8. The z-score is calculated as (X - μ) / σ, where X is the value, μ is the mean, and σ is the standard deviation. So, the z-score for 104.8 is (104.8 - 103.4) / 15.2 = 0.0921. We can then use a standard normal distribution table or a calculator to find the Show more…
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