A population of values has a normal distribution with μ = 154.3 μ = 154.3 and σ = 56.8 σ = 56.8 . You intend to draw a random sample of size n = 19 n = 19 . Find the probability that a single randomly selected value is greater than 112.6. P(X > 112.6) = Find the probability that a sample of size n = 19 n = 19 is randomly selected with a mean greater than 112.6. P(M > 112.6) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Added by Erin D.
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6. The z-score is calculated as (X - μ) / σ, where X is the value, μ is the mean, and σ is the standard deviation. So, the z-score for 112.6 is (112.6 - 154.3) / 56.8 = -0.7345. The probability that a single randomly selected value is greater than 112.6 is the Show more…
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