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A population of values has a normal distribution with μ = 188.1 and σ = 54.7. You intend to draw a random sample of size n = 100. Find the probability that a single randomly selected value is between 188.1 and 202.3. P(188.1 < X < 202.3) = Find the probability that a sample of size n = 100 is randomly selected with a mean between 188.1 and 202.3. P(188.1 < M < 202.3) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. CNNBC recently reported that the mean annual cost of auto insurance is 1036 dollars. Assume the standard deviation is 300 dollars. You take a simple random sample of 70 auto insurance policies. Find the probability that a single randomly selected value is less than 978 dollars. P(X < 978) = Find the probability that a sample of size n = 70 is randomly selected with a mean less than 978 dollars. P(M < 978) = Enter your answers as numbers accurate to 4 decimal places. Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 158000 dollars. Assume the standard deviation is 34000 dollars. Suppose you take a simple random sample of 89 graduates. Find the probability that a single randomly selected policy has a mean value between 147188 and 162685.2 dollars. P(147188 < X < 162685.2) = (Enter your answers as numbers accurate to 4 decimal places.) Find the probability that a random sample of size n = 89 has a mean value between 147188 and 162685.2 dollars. P(147188 < M < 162685.2) = (Enter your answers as numbers accurate to 4 decimal places.)

          A population of values has a normal distribution with μ = 188.1 and σ = 54.7. You intend to draw a random sample of size n = 100. Find the probability that a single randomly selected value is between 188.1 and 202.3. P(188.1 < X < 202.3) = Find the probability that a sample of size n = 100 is randomly selected with a mean between 188.1 and 202.3. P(188.1 < M < 202.3) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

CNNBC recently reported that the mean annual cost of auto insurance is 1036 dollars. Assume the standard deviation is 300 dollars. You take a simple random sample of 70 auto insurance policies. Find the probability that a single randomly selected value is less than 978 dollars. P(X < 978) = Find the probability that a sample of size n = 70 is randomly selected with a mean less than 978 dollars. P(M < 978) = Enter your answers as numbers accurate to 4 decimal places.

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 158000 dollars. Assume the standard deviation is 34000 dollars. Suppose you take a simple random sample of 89 graduates. Find the probability that a single randomly selected policy has a mean value between 147188 and 162685.2 dollars. P(147188 < X < 162685.2) = (Enter your answers as numbers accurate to 4 decimal places.) Find the probability that a random sample of size n = 89 has a mean value between 147188 and 162685.2 dollars. P(147188 < M < 162685.2) = (Enter your answers as numbers accurate to 4 decimal places.)

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