00:01
In this problem we are given that there is a population and the values that we have in this population, let's represent that with the random variable x, this is normally distributed, such that the mean of the distribution, this is 183 .7.
00:18
And the standard division of the distribution that's equal to 7 .3.
00:22
And we select a value randomly and we have to determine the probability that this value is more than 178 .6.
00:31
So here we first use this formula, and let's get the z score corresponding to this ros core.
00:37
So when we put the value of x as 178 .6, along with the other variables, we will get the z score as 178 .6 minus 183 .7 divided by 7 .3.
00:50
So this comes out to be minus 0 .7.
00:53
And we can now say that the probability that x is more than 178 .6, this will be equal to the probability that the probability that the z score is more than minus 0 .7 and that will be one minus probability that the z score is less than minus 0 .7 and using the z table we get the probability that the z score is less than minus 0 .7 as 0 .2420 and subtracting this from 1 we get 0 .7580 as the result and in the next part it is stated that we choose a sample of 10 values from the population and we have to determine the probability that their main value is more than 178 .6...