00:01
Hi, in the given problem, potential difference between the plates of parallel plate capacitor is given as 10 ,000 volt and the proton, which is moving between these two plates from positive plate to negative plate, that is having a charge e as plus 1 .6 into 10 .m minus 19 kulam.
00:25
And its mass is 1 .67 into 10 dash par minus 27 kilograms.
00:33
Now, when this charge will be traveling, will be passing through this potential difference from positive plate to negative plate, our work will be done on it.
00:47
And that work done on the charged particle, on the proton, work done on the proton.
00:58
To move it across the potential difference will be converted into its kinetic energy.
01:22
Hence, in the first part of the problem, we have to find kinetic energy.
01:28
So that is given as the work done, which is given by the expression q into delta v.
01:35
So here it is e delta v...