"A potentiometer wire of length 1 m has a resistance of 10 ?. It is connected to a 6 V battery in series with a resistance of 5?. Determine the emf of the primary cell which gives a balance point at 40 cm."
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Step 1
Given: Resistance of potentiometer wire, R = 10 ohms Resistance of battery, r = 5 ohms Voltage of battery, V = 6 V Total resistance in the circuit, R_total = R + r = 10 ohms + 5 ohms = 15 ohms Using Ohm's Law, V = IR 6 V = I * 15 ohms I = 6 V / 15 ohms I = 0.4 A Show more…
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