00:01
Hearing this problem given a pound of allure of lead and nickel weighs 14 .4 ounces in water where lead loses one 11th of its weight and nickel loses one ninth of its weight how much of each metal is in alloy let x be the weight of lead in ounce let x be the weight of lead in ounce in the alloy and y be the weight of nickel in ounce now the alloy is one pound and we know one pound is 60 now so we can write x plus y is equal to 16 this is the first equation then we'll calculate the loss of weight in water that will be 16 ounce minus 14 .4 ounce and that is 1 .6 ounce.
01:27
Now weight loss of lead will calculate weight loss of lead that lead loses 1 11th of his weight and nickel loses 1 9th of his weight.
01:39
So we'll write weight loss of lead that will be 1 .11th of its weight.
01:50
Its weight which is x and then we'll find out weight loss of nickel that will be one ninth of its mass this is one ninth of y so we can write x over 11 plus y over 9 that is equal to 1 .6 now the lcm of 11 and 9 is 99 99 divided by 11 9 9 times 6x 99 divided by 9 .11, 11 times y, 11y is 1 .6.
02:29
So we can write 9x plus 11y is 99 times 1 .6.
02:36
That is equal to 158 .4.
02:39
This is the second equation.
02:42
Now we take second equation, then we multiply the first equation with 9, then we subtract.
02:50
So 2 minus 1 times 5.
02:53
This is the second equation.
02:56
First equation multiplied by 9 will be 9x plus 9y is equal to 144...