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QUESTIONS A power plant operating with the rankine cycle is established to obtain electrical energy from a geothermal well. It is known that the maximum temperature that geothermal water can reach is 380 C. It is accepted that the efficiency of the geothermal boiler providing heat to the cycle is 100% (ideal), and the isentropic efficiency of the turbine and pump is 87%. At the turbine inlet, the steam will be saturated steam and the outlet pressure will be 150 kPa. Since the net power obtained from this facility is 3 MW; a) Draw the operating diagram of the facility. b) Show the cycle in the T-S diagram. c) Find the thermal efficiency of the plant. d) Find the steam rate used in the facility.

          QUESTIONS
A power plant operating with the rankine cycle is established
to obtain electrical energy from a geothermal well. It is known
that the maximum temperature that geothermal water can
reach is 380 C. It is accepted that the efficiency of the
geothermal boiler providing heat to the cycle is 100% (ideal),
and the isentropic efficiency of the turbine and pump is 87%.
At the turbine inlet, the steam will be saturated steam and
the outlet pressure will be 150 kPa. Since the net power
obtained from this facility is 3 MW;
a) Draw the operating diagram of the facility.
b) Show the cycle in the T-S diagram.
c) Find the thermal efficiency of the plant.
d) Find the steam rate used in the facility.
        
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QUESTIONS
A power plant operating with the rankine cycle is established
to obtain electrical energy from a geothermal well. It is known
that the maximum temperature that geothermal water can
reach is 380 C. It is accepted that the efficiency of the
geothermal boiler providing heat to the cycle is 100% (ideal),
and the isentropic efficiency of the turbine and pump is 87%.
At the turbine inlet, the steam will be saturated steam and
the outlet pressure will be 150 kPa. Since the net power
obtained from this facility is 3 MW;
a) Draw the operating diagram of the facility.
b) Show the cycle in the T-S diagram.
c) Find the thermal efficiency of the plant.
d) Find the steam rate used in the facility.

Added by John G.

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A power plant operating with the Rankine cycle is established to obtain electrical energy from a geothermal well. It is known that the maximum temperature that geothermal water can reach is 380°C. It is accepted that the efficiency of the geothermal boiler providing heat to the cycle is 100% (ideal), and the isentropic efficiency of the turbine and pump is 87%. At the turbine inlet, the steam will be saturated steam and the outlet pressure will be 150 kPa. Since the net power obtained from this facility is 3 MW: a) Draw the operating diagram of the facility. b) Show the cycle in the T-S diagram. c) Find the thermal efficiency of the plant. d) Find the steam rate used in the facility.
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An ideal Rankine steam cycle modified with two closed feedwater heaters is shown below. The power cycle receives $75 \mathrm{kg} / \mathrm{s}$ of steam at the high pressure inlet to the turbine. The feedwater heater exit states for the boiler feedwater and the condensed steam are the normally assumed ideal states. The fraction of mass entering the high pressure turbine at state 5 that is extracted for the feedwater heater operating at $1400 \mathrm{kPa}$ is $y=0.1446 .$ Use the data provided in the tables given below to (a) Sketch the $T$ -s diagram for the ideal cycle. (b) Determine the fraction of mass, $z$, that is extracted for the closed feedwater heater operating at the $245 \mathrm{kPa}$ extraction pressure. (c) Determine the required cooling water flow rate, in $\mathrm{kg} / \mathrm{s}$, to keep the cooling water temperature rise in the condenser to $10^{\circ} \mathrm{C}$. Assume $c_{p}=4.18 \mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K}$ for cooling water (d) Determine the net power output and the thermal efficiency of the plant.

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Transcript

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00:01 So let's see here.
00:02 We now have this crazy setup here.
00:06 That's very interesting.
00:08 It's illustrated in the book, and i've tried to reproduce it somewhat in my schematic here.
00:15 So let's see here.
00:18 We have, let me just kind of talk through it here a little bit.
00:25 Coming out at the condenser.
00:29 So we have a, let's see here, i didn't really.
00:32 Draw that, but we have, this is a flow in and out.
00:39 Let's basically, let's actually draw it as a closed system here, so flow in and out from cooling water.
00:49 So here's our condenser.
00:51 It's being, you know, cooled with cooling water here.
00:54 We have the output from the turbine coming in, and then we also have the output from the steam traps coming into it.
01:03 Then we have it coming out to the pump.
01:07 Going through two closed feed water heaters.
01:13 And so heating up to heating it up some and then heating it up again.
01:18 And the heat exchange from those closed feed water heaters come from two, two taps in our two pressure bleeds or two bleeds in our turbine.
01:29 One at a little two different points here.
01:34 One at 1 .4 megapascals and one at 245 kilopascals.
01:42 And then they come into here, and then we have these steam traps where, again, the steam traps help, you know, if there's any steam left, you know, if this hasn't condensed fully or this hasn't condensed fully, then we will get it here.
02:04 But again, that's usually, in this problem, we're not going to really analyze this.
02:10 We're going to assume that essentially it's condensed and we got full, you know, we got full heat transfer here.
02:17 And this was all kind of condensed.
02:20 This was condensed liquid and then this winds up being condensed liquid afterwards.
02:26 As it goes from 6 to 0 .9.
02:30 Yeah, so here to here.
02:33 So if there was any steam in here, then we'd get kind of trap it into here.
02:38 So we didn't put it back into there, which i'll put it back into the, i'm not sure why you actually even need to do that.
02:48 But there's a problem.
02:49 I'm sure there's a good reason.
02:50 I'm not a power plant engineer, so i'm not exactly sure why these would come into play.
02:58 So anyway, you can see in the ts diagram, we have a pretty big mess here.
03:02 So anyway, we get this coming out, heating up, heating up some more, going into the boiler, getting, you know, heating up some more into a saturated vapor turbine, and then some of it, some of it bleeds off here, some of it pleads off here, and the rest of it goes back to condenser.
03:19 And then the bleed stuff comes in.
03:23 He's all wind up nine, eight, nine, and eleven are saturated vapor or saturated liquid.
03:33 And so then we come back here and then we mix that back in with this and then we go.
03:41 So how does this look on here? so we go from one to two to three heating up some more to four heating up some more and then we boil it or then we keep heating it into the boiler and then we boil it and then we superheat it.
04:02 Comes into the turbine, some comes off here, so the fraction y comes off here, and we have 1 minus y continuing through the turbine.
04:14 Then we have another fraction z coming off at 7, and we have 1 minus y minus z continuing through the turbine.
04:22 Then we have 1 minus y minus z going into the contensor.
04:27 So then at this 6 point we have 6 going to 9.
04:33 So it gets basically it cools down and then it condenses while it's giving up heat.
04:45 And you can see that we have these temperatures here are the same, which is where kind of inefficiencies would happen because you wouldn't really have the same temperature coming out here because you wouldn't get a perfect transfer of energy here, thermal energy.
05:00 Now, so then from cit 9, we go to 10, which is basically just is cooling things down a bit.
05:11 So the steam trap, we basically cool things down a little bit in there.
05:17 And we increase some entropy.
05:20 Now, it's odd.
05:25 Yeah, i mean, is there, i think, i think, let's see here.
05:29 Did i try to remember the whole analysis here.
05:33 Oh, we never had to calculate.
05:37 The heat transfer out.
05:41 That is why i didn't do that.
05:45 Because the heat transfer out, you probably have some heat transfer out here and here too.
05:51 So you're, you know, you're dumping heat here and here and here.
05:57 Because again, as we go from here to here.
06:05 So then it comes down to 10 and then it comes to 11 where it mixes in here.
06:12 With stuff coming off from seven.
06:15 So seven and ten it's coming here and here mix and then we go to 11 and then we come down here to 12 through this steam trap and then these this mixes with this in the condenser so we have the point 176 over the last 15 then we have we have everything we need so hopefully i've described this system in enough detail that you can follow what is going on here.
06:48 We're also told what y is.
06:51 So whatever, it's 14 .5 % basically.
06:54 So about 14 .5 % is coming out of here.
06:58 We don't know what z is yet, but i'll figure that out.
07:01 Okay, so let's start with the pump.
07:04 So we can get the power into the pump as usual.
07:06 And we can get the anthropia 2 as usual.
07:09 The anthopy at 3 and at 11 are the same, again, because we're assuming perfect, you know, transfer energy here.
07:21 And it's also the same as the anthope at 12, we're going to assume.
07:29 Let's see here.
07:31 And that all winds up being this plus this.
07:34 No.
07:36 Enthope at 3 we can get because, what are we? using it three here i didn't write a lot of the probably i should have written more of this stuff down um oh yeah because it's it's basically at 11 it is a it is a condensed uh it's a saturated fluid at 11 and we know the enthalpyate 11 and 3 and 12 are going to be the same or going to assume that they're same.
08:18 So let's see here.
08:20 Then we get the entropy at four eight, four, nine, and ten.
08:24 Okay, so then four, nine, and ten.
08:30 Because we know, let's see, four, again, it's now again at four, not nine, we have a saturated, saturated, saturated liquid.
08:46 So, and then at ten, again, again, again, again, again.
08:49 We're assuming that we're not having any changes there.
08:52 You know, this is kind of a enthalpy, constant end -of -constant, and then at four, it's also the same.
09:01 Okay, so again, these are a lot of assumptions that we're not necessarily told to us, but we're kind of, you know, making them anyway, because again, there's, you can, they're, we're assuming that there's no heat transfer here, which is kind of weird by assuming that these are the same because there's a drop in temperature, of course.
09:31 But if you did an energy balance on this and there's no work, no external work and no heat transfer, then these entopies would be the same.
09:40 So it's kind of, i'm not exactly sure how our steam trap works, but anyway, we're basically assuming there's no heat energy flowing, no heat flowing in or out here or here.
09:54 Okay, and then we have perfect heat transfer through there...
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