00:01
Dear students, question is, when a mixture of potassium iodide and potassium chloride is titrated with silver nitrate, the first precipitate scene will be silver chloride, whether that is true or false.
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We have to find out.
00:19
Now this is a question on solubility product.
00:25
Solubility product.
00:29
Now the solution contains both chloride and iodide ions.
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So, when we are adding silver nitrate, then silver ions will combine with chloride and iodide and silver chloride and silver iodide will form.
00:45
And whose ionic product will cross the solubility product, then that will form the precipitate first.
00:52
So we have to check whose solubility product is lower, whether it is silver chloride or silver now, the table shows solubility product of a gcl at 25 degrees celsius is 1 .5625 multiplied by 10 to the power minus 10.
01:12
Similarly, solility product of silver iodide is, it is 8 .7 multiplied by 10 to 0 .17...