A professor wants to estimate how many hours per week her student study. A simple random sample a 51 student had a mean of 15 hours of studying per week. Construct a 90% confidence interval for the main number of hours of student studies per week. Assume that the population standard deviation is known to be 2.1 hours per week
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Step 1
Given that the confidence level is 90%, we need to find the z-score that corresponds to this confidence level. The z-score for a 90% confidence level is 1.645. Margin of error = z * (population standard deviation / sqrt(sample size)) Margin of error = 1.645 * (2.1 Show more…
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