00:01
We have the values for x and y as 4 .9, 3 .8, 4 .7, 3 .2, 4 .4, 3 .5, 4 .2, 2 .5, 3 .9, 1 .9, 3 .6, so now we can calculate its x bar and y bar values which are the means which are the sum of their corresponding values divided by the sample size 6.
00:42
So once calculated we get the means as 4 .2832 .850.
00:55
0 now we can use these values to get our corresponding x minus x bar y minus y bar x minus x bar squared y minus y bar squared and lastly we will have x minus x bar into y minus y bar.
01:31
So now we subtract 4 .3 and 4 .283 to get 0 .617.
01:44
So it would be 0 .417, 0 .117, 0 .1017, minus 0 .083, minus 0 .383, and minus 0 .683...