00:01
It is given that a projectile is fired from the ground and it follows a parabolic path.
00:08
So first let us draw the given parabolic path.
00:13
So here we have the coordinate system, we have x -axis and y -axis and the projectile is following a parabolic path.
00:25
So it is fired from the ground.
00:28
Let the velocity of the projectile be denoted as v.
00:31
We have angle theta that makes with the that the projectile makes with the x -axis.
00:38
So let this be the, let this point be the top of the path that is followed by the projectile.
00:48
Now we know that the total energy of the system, te, is given by kinetic energy of the system plus the potential energy of the system.
01:01
And we know that according to the conservation of energy, total energy of a system should be constant.
01:11
Now, the expression for potential energy is given by m, g h, where m is mass of the object.
01:20
G is the acceleration due to gravity and h is the height...