Given:
Initial horizontal velocity, \(v = 9.00 \, \text{m/s}\)
Time, \(t = 0.550 \, \text{s}\)
The horizontal distance traveled is given by:
\[ \text{Horizontal distance} = v \times t \]
\[ \text{Horizontal distance} = 9.00 \, \text{m/s} \times 0.550 \, \text{s}
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