Question

A projectile is launched at an angle of 13.0 degrees above the horizontal. What is its initial speed if it hits a target that is located a horizontal distance of 140m from the launch point and elevated 15.0 m from the launch level?

Name: a projectile is launched at an angle of 130 degrees above the horizontal what is its initial speed if it hits a target that is located a horizontal distance of 140m from the launch point and 65053
Uploaded: 2022-09-21T16:02:10-08:00
Duration: 4 min 55 s
Channel: Prabhat Tyagi
Description: a projectile is launched at an angle of 130 degrees above the horizontal what is its initial speed if it hits a target that is located a horizontal distance of 140m from the launch point and 65053

          A projectile is launched at an angle of 13.0 degrees above the
horizontal. What is its initial speed if it hits a target that is
located a horizontal distance of 140m from the launch point and
elevated 15.0 m from the launch level?

Added by Ramon M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhat Tyagi

09/21/2022

Step 1

Step 1: Calculate the horizontal component of the initial velocity: Given that the horizontal distance is 140m and the angle of launch is 13 degrees, we can use the equation: \[ x(t) = v_{x} \times t \] \[ 140 = v_{0} \times \cos(13) \times t \] \[ t = Show more…

Show all steps

Thanks for your feedback!

A projectile is launched at an angle of 13.0 degrees above the horizontal. What is its initial speed if it hits a target that is located a horizontal distance of 140m from the launch point and elevated 15.0 m from the launch level?