00:01
All right, so we have a projectile launched at 43 .5 meters per second at an angle of 25 degrees with the horizontal.
00:08
And then it hits some wall, and we want to know how high up and how far over it hits.
00:16
So we're looking for a delta x, so the change in the x position and the change in the y position, delta y.
00:27
And we're told that this happens at t equals 2 .90 seconds.
00:36
So first we have to split up this velocity, this initial velocity, into its x and y components.
00:44
So the initial in the x direction is just going to be that magnitude of 43 .5 meters per second times the cosine of the angle.
00:54
And for vii, y, it's that magnitude of the velocity times the sign of the angle, which is 25 degrees.
01:05
So for delta x, since there's no acceleration in the horizontal direction, we can just say that the change in the x position is the initial x times the time.
01:26
That it takes...