"A projectile thrown with an initial speed u and angle of projection 15o to the horizontal has a range R. If the same projectile is thrown at an angle of 45o to the horizontal with speed 2u, its range will be"
Added by Simon S.
Step 1
The range R of this projectile can be calculated using the formula: R = (u^2 * sin(2θ)) / g where u is the initial speed, θ is the angle of projection, and g is the acceleration due to gravity. Now, let's consider the projectile thrown at an angle of 45 degrees Show more…
Show all steps
Your feedback will help us improve your experience
Kamlesh Goyal and 84 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A projectile thrown with an initial speed $u$ and angle of projection $15^{\circ}$ to the horizontal has a range $R$. If the same projectile is thrown at an angle of $45^{\circ}$ to the horizontal with speed $2 u$, its range will be (a) $12 R$ (b) $3 R$ (c) $8 R$ (d) $4 R$
A projectile thrown with an initial speed u and the angle of projection 15 degrees to the horizontal has a range R. If the same projectile is thrown at an angle of 45 degrees to the horizontal with speed 2u, what will be its range?
Deepak J.
A projectile fired with initial velocity u at some angle ? has a range R. If the initial velocity be doubled at the same angle of projection, then the range will be
Dharmendra M.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD