Question

A projectile was fired across level ground at an initial velocity of 105 m/s at an angle of 35∙0\deg above the horizontal. Calculate: a) the maximum height reached (above the ground); b) the time of flight; b) and the range of the projectile (where it hits the ground).

Name: a projectile was fired across level ground at an initial velocity of 105 ms at an angle of 350deg above the horizontal calculate a the maximum height reached above the ground b the time of f 12077
Uploaded: 2022-04-04T12:58:11-08:00
Duration: 4 min 28 s
Channel: Shaiju T
Description: a projectile was fired across level ground at an initial velocity of 105 ms at an angle of 350deg above the horizontal calculate a the maximum height reached above the ground b the time of f 12077

          A projectile was fired across level ground at an initial velocity of 105 m/s at an angle of 35∙0\deg  above the horizontal. Calculate:
a) the maximum height reached (above the ground);
b) the time of flight;
b) and the range of the projectile (where it hits the ground).

Added by Dennis P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shaiju T

04/04/2022

Step 1

To do this, we use the following formulas: - Vertical initial velocity (Viy) = Vi * sin(θ) - Horizontal initial velocity (Vix) = Vi * cos(θ) Given: - Initial velocity (Vi) = 105 m/s - Angle (θ) = 35.0° Calculations: - Viy = 105 * sin(35.0°) ≈ 61.03 m/s - Vix = Show more…

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A projectile was fired across level ground at an initial velocity of 105 m/s at an angle of 35∙0\deg above the horizontal. Calculate: a) the maximum height reached (above the ground); b) the time of flight; b) and the range of the projectile (where it hits the ground).