A proton and an electron are fixed in space with a separation of 899 nm. Calculate the electric potential at the midpoint between the two particles. potential: V Find the magnitude of the electric field at the same point. magnitude of field: N/C The direction of field is toward the proton. toward the electron. another direction. undetermined.
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6 \times 10^{-19} \, \text{C} \) is the charge of the proton, \( q_2 = -1.6 \times 10^{-19} \, \text{C} \) is the charge of the electron, and \( d_1 = d_2 = 899 \times 10^{-9} \, \text{m} \) is the distance between the particles. Show more…
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