00:01
Here in this question we are going to find out the length of the box.
00:06
So we know that the allowed energies of a particle confined to a one -dimensional box of length l is given by e .n equals to n square multiply by h squared divided by 8 multiplied by m multiply by l square.
00:31
Now, according to the above formula, the allowed energy of a proton in the n -equal one state of a one -dimensional box is given by e1 equals to one whole square multiplied by h square divided by 8 multiplied by m multiplied by l square.
01:00
E1 equals to h squared divided by 8 multiplied by m multiplied by l square.
01:11
Now similarly the allowed energy of a proton in the n equal to two state of a one dimensional box is given by e2 equals to two whole square multiplied by h whole square divided by 8 multiplied by m multiplied by l square.
01:45
So from above we get e2 equals to 4 multiply by h squared divided by 8 multiply by m multiply by l square.
01:56
Now here we have given that a proton confined in a one -dimensional box emits a 2 mega electron volt gamma ray photon in a quantum germ from n equal 2 to n equal 1.
02:13
Then e2 minus e1 equals to 2 mega electron volt.
02:29
Or we can write this as e2 minus e1 equals to 2 multipliol...