Question

A proton is traveling along a horizontal line directed to the north with a velocity of $2e+06$ m/s when a horizontal and uniform magnetic field of 2.9 T pointed due east is turned on. The proton will begin to move in a circular path. What is the radius of this path? 0.0071983 m 0.060538 m 0.0035991 m 14397 m

          A proton is traveling along a horizontal line directed to the north with a velocity of $2e+06$ m/s when a horizontal and uniform magnetic field of 2.9 T pointed due east is turned on. The proton will begin to move in a circular path. What is the radius of this path?
0.0071983 m
0.060538 m
0.0035991 m
14397 m
        
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A proton is traveling along a horizontal line directed to the north with a velocity of 2e+06 m/s when a horizontal and uniform magnetic field of 2.9 T pointed due east is turned on. The proton will begin to move in a circular path. What is the radius of this path?
0.0071983 m
0.060538 m
0.0035991 m
14397 m

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A proton is traveling along a horizontal line directed to the north with a velocity of 2e+6 m/s when a horizontal force pointed due east is turned on. The proton will begin to move in a circular path. What is the radius of this path? 0.007193 m, 0.060538 m, 0.0035991 m.
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Transcript

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00:01 For a charged particle moving perpendicular to a uniform magnetic field the radius of the circular path traced by the charged particle is given by mass of the particle times speed over charge on the particle times the magnetic field now from this we can write the magnetic field equals mv over qr now let's substitute the values…
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