Given:
Initial velocity of proton, \(v_0 = 4.20 \times 10^6 \, \text{m/s}\)
Acceleration, \(a = -2.845 \times 10^{14} \, \text{m/s}^2\) (negative sign indicates retardation)
We can use the equation \(v = v_0 + at\) where \(v\) is the final velocity (0 m/s in this
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