00:01
Hi, here in this given problem, speed of the proton in the magnetic field that is given as v is equal to 4 .0 into 10 raise to the power 7 meter per second.
00:23
Earth's magnetic field here, that is 1 .0 into 10 raised to the power minus 6 tesla and angle between the magnetic field vector and velocity vector.
00:40
This angle is given as 25 degrees.
00:44
Now in the first part of the problem, as the chart particle is not entering perpendicular to the magnetic field, it is making an angle with the direction of magnetic field.
00:55
So it will not make a complete circle, actually it will make a helix and radius of that helix.
01:10
This is given by an expression m v.
01:13
Sine theta by b into q, q is the charge over protons.
01:19
So we write it e, b, e.
01:22
So plugging in the known values for the mass of the proton, this is 1 .67 into 10 -p.
01:29
Minus 27 into v, 4 into 10 to the power 7 into sine 25 degree, divided by 1 .0 into 10 to power minus 6...