A proton moving from negative plate to the positive plate of parallel-plate arrangement. The plate are 1.5 cm apart and the field is uniform with a magnitude of 1500N * C ^ - 1 Calculate: ii) The electric potential difference (voltage) between the plate. i) The change in the proton's electric potential energy
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- Distance between the plates, \( d = 1.5 \, \text{cm} = 0.015 \, \text{m} \) - Electric field magnitude, \( E = 1500 \, \text{N/C} \) Show more…
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