Given:
Charge of proton, q = $1.6 \times 10^{-19}$ C
Velocity of proton, v = $3.0 \times 10^{6}$ m/s
Magnetic field, B = 0.30 T
Angle, $\theta$ = 37°
The magnetic force on the proton can be calculated using the formula:
$F_{B} = qvB\sin(\theta)$
Substitute the
Show more…