Question

A proton travels with a speed of 5.0× 10? m/s in a direction that makes an angle of 60.0° with the direction of a magnetic field of magnitude 11.6 T. What is the magnitude of the magnetic force on the proton ( in units of pN)?

Name: A proton travels with a speed of 5.0× 10? m/s in a direction that makes an angle of 60.0° with the direction of a magnetic field of magnitude 11.6 T. What is the magnitude of the magnetic force on the proton ( in units of pN)?
Uploaded: 2022-04-06T22:55:55-08:00
Duration: 2 min 29 s
Channel: Rashmi Prakash
Description: A proton travels with a speed of 5.0× 10? m/s in a direction that makes an angle of 60.0° with the direction of a magnetic field of magnitude 11.6 T. What is the magnitude of the magnetic force on the proton ( in units of pN)?

          A proton travels with a speed of 5.0× 10? m/s in a direction that makes an angle of 60.0° with the direction of a magnetic field of magnitude 11.6 T. What is the magnitude of the magnetic force on the proton ( in units of pN)?

A proton travels with a speed of 5.0× 10? m/s in a direction that makes an angle of 60.0° with the direction of a magnetic field of magnitude 11.6 T. What is the magnitude of the magnetic force on the proton ( in units of pN)?

Added by Irene W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Rashmi Prakash

04/06/2022

Step 1

Given that the velocity of the proton is 5.0 x 10^6 m/s and the magnetic field strength is 11.6 T, we can calculate the cross product as: \(v \times B = vB \sin(\theta)\) where \(v = 5.0 \times 10^6\) m/s, \(B = 11.6\) T, and \(\theta = 60^\circ\). \(v \times B = Show more…

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A proton travels with a speed of 5.0× 10⁶ m/s in a direction that makes an angle of 60.0° with the direction of a magnetic field of magnitude 11.6 T. What is the magnitude of the magnetic force on the proton ( in units of pN)?