Given the scale is 1:5, which means the length scale ratio is $L_r = \frac{1}{5}$.
The velocity ratio is $\frac{V_m}{V} = L_r = \frac{1}{5}$.
The drag force ratio is $\frac{D}{D_m} = \frac{V_m}{V} = \frac{1}{5}$.
Therefore, the drag force on the prototype is $D_p
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