00:01
Okay, so here in this question we are given the initial velocity v0 equal to 35 feet per second and theta is 60 degree from vertical.
00:14
So the value of alpha will be 90 degree minus 60 which is equal to 30 degree from horizontal and the acceleration due to gravity is 32 .2 feet per second square.
00:27
So we have the colon equation for the projectile motion.
00:31
First, for the horizontal motion, we have x equal to v0 cost alpha times t.
00:47
Let this be a first equation and the second for the vertical motion.
00:56
We have y equal to h plus v0 sine alpha time t minus half times g times t squared.
01:07
And let this be our second equation.
01:09
Now, substituting value of 3 from equation first to equation second, we have y equal to h plus v0, sine alpha times x over v0, cos alpha minus half times c times x square over v0 square times cos square alpha...