A quadratic function f is given. f(x)=x^(2)-4x+5 (a) Find the vertex and x - and y-intercepts of f. (If an answer does not exist, enter DNE.)
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The vertex of a quadratic function in the form \( f(x) = ax^2 + bx + c \) can be found using the formula for the x-coordinate of the vertex: \[ x = -\frac{b}{2a} \] For the function \( f(x) = x^2 - 4x + 5 \), we have \( a = 1 \) and \( b = -4 \). Show more…
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