Question

A quantity of 0.0246 mol of a gas initially at 0.0500 L and 20.0 °C undergoes a co done (in joules) by the gas if it expands (a) against a vacuum and (b) against a c correct number of significant digits. Part 1 of 2 work done against a vacuum: J Part 2 of 2 work done against the pressure of 0.450 atm: J

          A quantity of 0.0246 mol of a gas initially at 0.0500 L and 20.0 °C undergoes a co
done (in joules) by the gas if it expands (a) against a vacuum and (b) against a c
correct number of significant digits.
Part 1 of 2
work done against a vacuum:
J
Part 2 of 2
work done against the pressure of 0.450 atm:
J

A quantity of 0.0246 mol of a gas initially at 0.0500 L and 20.0 °C undergoes a co
done (in joules) by the gas if it expands (a) against a vacuum and (b) against a c
correct number of significant digits.
Part 1 of 2
work done against a vacuum:
J
Part 2 of 2
work done against the pressure of 0.450 atm:
J

Added by Samuel A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert David Collins

03/19/2023

Step 1

Using the ideal gas law equation: PV = nRT where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.0821 L.atm/mol.K), and T is the temperature in Kelvin. Given: n = 0.0246 mol V_initial = 0.0500 L T = 20.0°C = 293.15 K Since Show more…

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A quantity of 0.0246 mol of a gas initially at 0.0500 L and 20.0°C undergoes a c done (in joules) by the gas if it expands (a) against a vacuum and (b) against a correct number of significant digits. Part 1 of 2 Work done against a vacuum: X Part 2 of 2 Work done against the pressure of 0.450 atm: X