A random sample of 25 fields of corn has a mean yield of 20.3 bushels per acre and standard deviation of 5.82 bushels per acre. Determine the \( 98 \% \) confidence interval for the true mean yield. Assume the population is approximately normal. Step 2 of 2: Construct the \( 98 \% \) confidence interval. Round your answer to one decimal place.
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Step 1
- Sample mean (\(\bar{x}\)) = 20.3 bushels per acre - Sample standard deviation (\(s\)) = 5.82 bushels per acre - Sample size (\(n\)) = 25 - Confidence level = 98% Show more…
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