A random sample of 250 individuals working in a large city indicated that 62 are dissatisfied with their working conditions. Based upon this, compute a \( 90 \% \) confidence interval for the proportion of all individuals in this city who are dissatisfied with their working conditions. Then find the lower limit and upper limit of the \( 90 \% \) confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.)
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The sample proportion (\( \hat{p} \)) is the number of individuals who are dissatisfied divided by the total number of individuals in the sample. Given that 62 out of 250 individuals are dissatisfied, the sample proportion is calculated as: \[ \hat{p} = Show more…
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A random sample of 300 individuals working in a large city indicated that 90 are dissatisfied with their working conditions. Based upon this, compute a 90% confidence interval for the proportion of all individuals in this city who are dissatisfied with their working conditions. Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult the formulas.) Lower limit: Upper limit:
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