Question

A random sample of 432 voters revealed that 100 are in favor of a certain bond issue. A 95 percent confidence interval for the proportion of the population of voters who are in favor of the bond issue is - 100 ± 1.645 sqrt((0.5 * 0.5) / 432) - 0.231 ± 1.645 sqrt((0.231 * 0.769) / 432) - 100 ± 1.96 sqrt((0.5 * 0.5) / 432) - 0.231 ± 1.96 sqrt((0.231 * 0.769) / 432)

          A random sample of 432 voters revealed that 100 are in favor of a certain bond issue. A 95 percent confidence interval for the proportion of the population of voters who are in favor of the bond issue is
- 100 ± 1.645 sqrt((0.5 * 0.5) / 432)
- 0.231 ± 1.645 sqrt((0.231 * 0.769) / 432)
- 100 ± 1.96 sqrt((0.5 * 0.5) / 432)
- 0.231 ± 1.96 sqrt((0.231 * 0.769) / 432)

A random sample of 432 voters revealed that 100 are in favor of a certain bond issue. A 95 percent confidence interval for the proportion of the population of voters who are in favor of the bond issue is
- 100 ± 1.645 sqrt((0.5 * 0.5) / 432)
- 0.231 ± 1.645 sqrt((0.231 * 0.769) / 432)
- 100 ± 1.96 sqrt((0.5 * 0.5) / 432)
- 0.231 ± 1.96 sqrt((0.231 * 0.769) / 432)

Added by Cynthia C.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Krishna G

02/01/2022

Step 1

\[ \hat{p} = \frac{100}{432} \approx 0.231 \] Show more…

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A random sample of 432 voters revealed that 100 are in favor of a certain bond issue. A 95 percent confidence interval for the proportion of the population of voters who are in favor of the bond issue is - 100 ± 1.645 sqrt((0.5 * 0.5) / 432) - 0.231 ± 1.645 sqrt((0.231 * 0.769) / 432) - 100 ± 1.96 sqrt((0.5 * 0.5) / 432) - 0.231 ± 1.96 sqrt((0.231 * 0.769) / 432)