Question

A random sample of n=1100 registered voters was taken and it was found that 570 would vote for the Republican candidate in a state senate race. Let p represent the proportion of registered voters who would vote for the Republican candidate. Consider testing H0: p = 0.50 Ha: p > 0.50. (a) The test statistic is z = (b). Regardless of what you actually computed, suppose your answer to part (a) was z = 1.28. Using this z, the p-value =

Name: a random sample of n1100 registered voters and found that 570 would vote for the republican candidate in a state senate race let p represent the proportion of registered voters who would vot 05879
Uploaded: 2022-04-17T11:17:57-08:00
Duration: 51 s
Channel: Cheng Zhang
Description: a random sample of n1100 registered voters and found that 570 would vote for the republican candidate in a state senate race let p represent the proportion of registered voters who would vot 05879

          A random sample of n=1100 registered voters was taken and it was found that 570 would vote for the Republican candidate in a state senate race. Let p represent the proportion of registered voters who would vote for the Republican candidate. Consider testing H0: p = 0.50 Ha: p > 0.50. (a) The test statistic is z = (b). Regardless of what you actually computed, suppose your answer to part (a) was z = 1.28. Using this z, the p-value =

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Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Cheng Zhang

04/17/2022

Step 1

- Sample size, \( n = 1100 \) - Number of voters for the Republican candidate, \( X = 570 \) - Sample proportion, \( \hat{p} = \frac{X}{n} = \frac{570}{1100} = 0.5182 \) - Null hypothesis, \( H_0: p = 0.50 \) - Alternative hypothesis, \( H_a: p > 0.50 \) Show more…

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A random sample of n=1100 registered voters was taken and it was found that 570 would vote for the Republican candidate in a state senate race. Let p represent the proportion of registered voters who would vote for the Republican candidate. Consider testing H0: p = 0.50 Ha: p > 0.50. (a) The test statistic is z = (b). Regardless of what you actually computed, suppose your answer to part (a) was z = 1.28. Using this z, the p-value =