A random variable follows the continuous uniform distribution between 170 and 360. Calculate the following quantities for the distribution.\na) P(220 ? x ? 330)\nb) P(170?x?280)\nc) P(x > 200)\nd) What are the mean and standard deviation of this distribution?\na) P(220 ? x ? 330) = \n(Type an integer or decimal rounded to three decimal places as needed.)\nb) P(170?x?280) = \n(Type an integer or decimal rounded to three decimal places as needed.)\nc) P(x > 200) = \n(Type an integer or decimal rounded to three decimal places as needed.)\nd) The mean of this distribution is \n(Type an integer or a decimal.)\nThe standard deviation of this distribution is \n(Type an integer or decimal rounded to two decimal places as needed.)
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The continuous uniform distribution is defined by the formula: f(x) = 1 / (b - a) where a is the lower bound and b is the upper bound of the distribution. In this case, a = 170 and b = 360. So, f(x) = 1 / (360 - 170) = 1 / 190. To calculate the probability Show more…
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