00:01
In this problem, we are given that there's a random variable x, and this is having normal distribution such that the mean of the distribution, that's 125, and the standard deviation, well, that's 16.
00:13
So we have to first find out the probability that this x is more than 156 .36.
00:20
So here we will simply use this formula, and let's get the z -score corresponding to this raw score.
00:26
So when we plug in the value of x as 156 .36, the z -score will be 156 .36 minus 125 divided by 16, which here simplifies to 1 .96.
00:40
And we can now say that the probability that x is greater than 156 .36, this will be equal to the probability that the z -score is greater than 1 .96, and that will be 1 minus probability that the z -score is less than 1 .96.
00:57
And using the z -table, we get this probability 0 .9750.
01:03
And subtracting that from one, we will get 0 .025 as the result...