A ray of light makes an angle of $25^{\circ}$ with the normal to a plane mirror. If the mirror is turned through $6.0^{\circ}$, making the angle of incidence $31^{\circ}$, through what angle is the reflected ray rotated?
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So, initially, the angle of reflection is also $25^{\circ}$. When the mirror is turned through $6.0^{\circ}$, the angle of incidence becomes $31^{\circ}$. Show more…
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