A reaction has x1dHx1crxn = -112 kJ and x1dSx1crxn = 354 J>K. At what temperature is the change in entropy for the reaction equal to the change in entropy for the surroundings?
Added by Julio P.
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Step 1:** Convert the given values of delta H and delta S into the correct units: - delta H = -112 kJ = -112,000 J - delta S = 354 J/K ** Show more…
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A reaction has $\Delta H_{\mathrm{rxn}}^{\circ}=-112 \mathrm{kJ}$ and $\Delta S_{\mathrm{rxn}}^{\circ}=354 \mathrm{J} / \mathrm{K}$ . At what temperature is the change in entropy for the reaction equal to the change in entropy for the surroundings?
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