A reaction has the experimental rate law of Rate = k[A]^2. What happens to the rate if the concentration of A is tripled? What happens to the rate if the concentration of A is reduced to one third the initial concentration?
Added by Julio R.
Step 1
Plugging this into the rate law, the new rate would be: Rate = k(3[A])^2 Rate = 9k[A]^2 ** Show more…
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A reaction has the following experimental rate equation: Rate $=k[\mathrm{A}]^{2}[\mathrm{B}] .$ If the concentration of $\mathrm{A}$ is doubled and the concentration of $\mathrm{B}$ is halved, what happens to the reaction rate?
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