00:01
Firstly, let's summarize this problem.
00:05
Mass of hydrogen gas equals 6 .54 kilograms.
00:16
And practical yield of mass of ammonia equals 30 .4 kilograms.
00:32
The task is to find the percentage yield of ammonia.
00:42
Firstly, let's write reaction equation, hydrogen gas plus nitrogen gas equals ammonia.
00:59
Let's balance here will be 2 and here will be 3.
01:05
Let's remind the molar masses of needed reactants.
01:09
Molar mass of hydrogen gas equals 2 .0 grams per mole.
01:16
And molar mass of ammonia equals 17 .0 grams per mole.
01:31
Now let's find the amount of hydrogen gas or the number of moles.
01:38
It will be mass divided by molar mass.
01:43
In this case, amount of hydrogen gas will be 6 .54 times 10.
01:52
In power 3 grams divided by 2 .0 grams per mole and we obtain 3 .27 times 10 in power 3 moles...