00:01
In this problem, it is said that we have a certain lockbox, and the access code for this consists of six digits.
00:07
The first digit cannot be one, and the last digit must be even, and we need to determine how many different codes are available.
00:14
So the code has six digits, one, two, three, four, five, and six.
00:20
Now note that the first digit cannot be one.
00:23
Now, there are a total of ten digits from zero to nine, and since the first digit cannot be one, we have ten minus one, that is, a total of nine different options to choose from when we select this first digit.
00:36
Now, the last digit must be even, and zero is considered an even number, so we can have zero or two or four or six or eight, so that's a total of five different options for this last digit...