A recent article in vitality magazine reported that the mean amount of leisure time per week for an American men is 40 hours. You believe this figure is too large and decide to conduct your own test. In a random sample of 60 men you find that the mean is 37.8 hours of leisure per week and that the standard deviation of the sample is 12.2 hours. Can you conclude that the information in this article is untrue? Use the .05 significance level. Determine the p-value and explain the meaning. 1. The critical value of T is -1.671 2. You are unable to reject the null hypothesis that the mean leisure time is 40 hours. 3. All of the others are true. 4. This is a one-tailed test
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Step 1
The null hypothesis (H0) is that the mean leisure time is 40 hours, as stated in the article. The alternative hypothesis (H1) is that the mean leisure time is less than 40 hours, which is what you believe. Show more…
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A recent article in Vitality magazine reported that the mean amount of leisure time per week for American men is 40.0 hours. You believe this figure is too large and decide to conduct your own test. In a random sample of 60 men, you find that the mean is 37.8 hours of leisure per week and that the standard deviation of the sample is 12.2 hours. Can you conclude that the information in the article is untrue? Use the .05 significance level. Determine the $p$ -value and explain its meaning.
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A 2010 article in Vitality magazine reported that the mean amount of leisure time per week for American men is 40.0 hours or more. You believe this figure is too large and decide to conduct your own test. In a random sample of 60 men, you find that the mean is 37.8 hours of leisure time per week and that the standard deviation of the sample is 12.2 hours. Can you conclude that the information in the article is untrue? Use the 0.05 significance level. What is the alternative hypothesis? The mean is equal to 40 hours. None of these The mean is less than 40 hours. The mean is greater than 40 hours. The mean is not equal to 40 hours.
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