A recent study evaluated how addicted teenagers become to nicotine once they start smoking. The response variable was the number of yes answers on a questionnaire called the Hooked on Nicotine Checklist (HONC). Of teenagers who had tried tobacco, the mean HONC score was 4.1 (s = 5.2) for the 150 females and 2.7 (s = 3.5) for the 182 males. Complete parts a through c below. a. Find the standard error comparing the sample means. Interpret. The standard error is se = 0.4976. (Round to four decimal places as needed.) What does the standard error indicate? A. The standard error is the difference in standard deviations for the two populations. B. The standard error is the standard deviation of the difference between $\bar{x}_1 - \bar{x}_2$ C. The standard error describes the spread of the sampling distribution of $\bar{x}_1 - \bar{x}_2$ D. The standard error is the standard deviation of the sample for this study.
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Given: Sample mean for females (x1) = 4.1 Sample standard deviation for females (s1) = 5.2 Sample size for females (n1) = 150 Sample mean for males (x2) = 2.7 Sample standard deviation for males (s2) = 3.5 Sample size for males (n2) = 182 The formula to Show more…
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A recent study evaluated how addicted teenagers become to nicotine once they start smoking. The response variable was the number of yes answers on a questionnaire called the Hooked on Nicotine Checklist (HONC). A subject was called a monthly smoker if he or she had smoked cigarettes over an extended period of time. The 77 female monthly smokers had a mean HONC score of 5.2 (s=3.4), and the 73 male monthly smokers had a mean HONC score of 3.9 (s=3.3). a. Find the test statistic and P-value for H0: μ1=μ2 and Ha: μ1≠μ2. Interpret, and explain what (if any) effect gender has on the mean HONC score. Use the significance level 0.05. The test statistic is: (Round to three decimal places as needed.) The P-value is: (Round to three decimal places as needed.)
Qudsiya A.
When people smoke, the nicotine they absorb is converted to cotinine, which is measured. The population standard deviation for cotinine levels in smokers is 15.6. A simple random sample of 40 smokers found a sample mean cotinine level of 165.5 and a sample standard deviation of 11.6. Use a 10% significance level to test the claim that the mean cotinine level of all smokers is more than 160.0. a. Identify the null and alternative hypotheses, writing them out using the symbols we used in class. b. State the level of significance. c. Calculate the test statistic, being sure to indicate if it is a z-score or a t-score. d. Calculate the p-value or find the critical number(s). e. State your decision to either reject the null hypothesis or fail to reject the null hypothesis. f. Restate the decision in the context of the claim in the problem in clear, plain English.
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