Question

A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position. The standard deviation of the sample was 6.2 weeks. Construct a 95% confidence interval for the population mean. (Round answers to 2 decimal places.)The confidence interval is between _ and _.

Name: a recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position the standard deviation of the sample was 62 74364
Uploaded: 2022-08-12T11:56:26-08:00
Duration: 3 min 10 s
Channel: Joanna Quigley
Description: a recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position the standard deviation of the sample was 62 74364

          A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position. The standard deviation of the sample was 6.2 weeks. Construct a 95% confidence interval for the population mean. (Round answers to 2 decimal places.)The confidence interval is between ___ and ___.

Added by Eduardo S.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Joanna Quigley

08/12/2022

Step 1

96, s = 6.2, and n = 50, we have: \(ME = 1.96 \times \frac{6.2}{\sqrt{50}} \approx 1.719\) Show more…

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A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position. The standard deviation of the sample was 6.2 weeks. Construct a 95% confidence interval for the population mean. (Round answers to 2 decimal places.)The confidence interval is between ___ and ___.