00:01
Hi, here in this given problem there is a uniform magnetic field directed towards right.
00:20
Within this magnetic field there is a rectangular current carrying loop which is carrying current i in a counter clockwise direction.
00:45
Length of this loop is given as l1 and its width is given as l2.
00:54
Magnetic field is b.
00:58
So, first of all using an expression for the magnetic force experienced by current carrying conductor in the magnetic field in vector form this is f bar is equal to i l cross b or we can say this is i l b sin theta.
01:22
So, in the first part of the problem force experienced by the upper and lower arms that will be 0 because the angle between current element and magnetic field these are 0 degree and 180 degree respectively.
02:12
And we know whether it is sin 0 degree or it is sin 180 degree both are 0.
02:20
Ok, then for the width means for the left side arm as theta is 90 degree.
02:39
So, force f1 i into l2 into b sin 90 degree means this is i l2 b.
02:56
Similarly, force on right side arm that is also f2 is equal to i l2 b...