00:01
Here the diagram is as follows.
00:03
Here, this is the uniform magnetic field, cross mark.
00:07
The magnitude of magnetic field is 2 .60 tesla and it is directed into the plane.
00:13
Inside this there is a rectangular loop with 7 cm length and 1 .8 cm width.
00:19
The resistance is 0 .8 o and it is moving to the right side with a velocity 3 meter per second.
00:26
Here in part a, first let us calculate the value of 1 .4 .2.
00:30
Emf.
00:32
When it is in motion, there will be an emf developed in the rectangular loop.
00:36
The value of emf is given by l into v into magnitude of the magnetic field.
00:42
Here the length l is, that is, 1 .8 into 10 power minus 2 meter into the velocity with which it is moving is 3 meter per second into the magnitude of magnetic field is 2 .60 tesla.
00:57
Upon solving we will get the emf to be 0 .1 1404 volt.
01:03
So this is the value of emf here.
01:07
Next we need to find out the value of current i is equal to the equation is emf divided by resistance are...