00:01
Specify the magnitude and line of action of our equivalent force for part a.
00:07
Okay, so for part a, we're given our angle is 40 degrees.
00:13
And we have these points ab, d, and c.
00:18
We can find our x component of our net force.
00:21
Our net force, x component is negative 15 degrees, or negative 15 times sine of 40 degrees plus 15 sine of 40 degrees equal to 0 because these are the forces that are on our problem.
00:43
Now for a y component, we have negative 15 cosine of 40 degrees plus 15 cosine of 40 minus 48 is equal to negative 48.
00:54
So we can find the magnitude.
00:57
We sum up fx squared plus fy squared to get 48 newtons.
01:06
So that's our magnitude...