Question

h oil 1m 2m 2m Water 3m Figure 1

          h
oil
1m
2m
2m
Water
3m
Figure 1

Added by Susan S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/19/2023

Step 1

We can set up an equation using the heights of the oil and water: V_oil = h * 2m * 6m V_water = (3m - h) * 2m * 6m Since the volume is constant, we can set these two equations equal to each other: h * 2m * 6m * 0.72 = (3m - h) * 2m * 6m Simplifying and solving Show more…

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A rectangular tank of internal width 6m is partitioned as shown in Figure 1 and contains oil and water. The oil's specific gravity is 0.72. A) What must h be? B) If the oil-water surface drops by a small distance (Î´), what will be the rise in the free surface of water with air? (Hint: Use constant volume of water) C) If a 1200-N block of wood is placed in flotation in the oil, what is the rise in the free surface of the water in contact with the air?