A red train traveling at 72 kmh and a green train traveling...

A red train traveling at 72 km/h and a green train traveling at 144 km/h are headed toward each other along a straight, level track. When they are 880 m apart, each engineer sees the other's train and applies the brakes. The brakes slow each train at the rate of 1.0 m/s2. Is there a collision? If so, give (a) the speed of the red train, (b) the speed of the green train, and (c) the separation between the trains when they collide (0 m). If not, give (a) the speed of the red train (0 m/s), (b) the speed of the green train (0 m/s), and (c) the separation between the trains when they stop.

Transcript

00:01 Hi, in this question it is given that there is a red train.

00:05 This red train moves with a speed of 72 km per hour.

00:11 That is the velocity of the train.

00:15 Red train is 72 kilometers per hour.

00:20 It has converted into meters per second.

00:24 72 divided by 1 hour contains 60 minutes.

00:29 One minute contains 60 seconds.

00:31 On calculation we obtained, the o equal to 20 meters per second.

00:43 And this train is moving with an acceleration of negative acceleration, that is a deceleration.

00:52 So we can write the acceleration of this train is minus 1 meter per second square.

01:03 And on another train which is coming in the opposite direction, so this train is moving towards right and this train is moving towards left both are on the same track and the speed of this train is given as that is the green train is given as 144 km per hour kilometers there are convert into meters per second they obtain 40 meters per second since this train is moving in the opposite direction we'll put their negative side so, negative sign.

01:48 And the acceleration of this train is also 1 meter per second square but is in the positive direction.

01:58 We need to find out whether these trains will collate or not.

02:03 So first of all let us determine the distance between these two trains.

02:08 So for that what we do, let us use the equation of motion to determine the distance traveled by the red train and the distance traveled to the green.

02:19 So delta x for the red train is equal to the final velocity square minus the initial velocity square divided by 2a.

02:34 Now let's plug the values even in the question is final velocity is going to be 0 minus 1 t squared by 2 into the negative acceleration 1 meter per second square and calculation we obtained 200 meters the distance traveled by the train is 200 now coming to the green train let us use the same equation delta x is equal to d square minus new square is nothing but here we have denoted with the b o so here also this is d o square divided by 2a...

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